More action, less planning

I've really got to get some things working instead of continuing to collect ideas or the project will collapse under a morass of constraints foisted by too many outlandish fun ideas.

Action Items

  1. Rendering two markdown dialects (markdeep, followed by a more vanilla one) to html, assembling the documents, and autogenerating both navigation and metadata.

  2. Then, I will be able to tweak visuals with css. That paves the way for the beginning of a theme system.

  3. Probably build the embedded images/videos workflow next after this so I can get into quickly making build logs of whatever kind of stuff I get up to.

Work log

Tests

pie title NETFLIX
         "Time spent looking for movie" : 90
         "Time spent watching it" : 10
sequenceDiagram
    Alice ->> Bob: Hello Bob, how are you?
    Bob-->>John: How about you John?
    Bob--x Alice: I am good thanks!
    Bob-x John: I am good thanks!
    Note right of John: Bob thinks a long<br/>long time, so long<br/>that the text does<br/>not fit on a row.

    Bob-->Alice: Checking with John...
    Alice->John: Yes... John, how are you?

When $a \ne 0$, there are two solutions to $(ax^2 + bx + c = 0)$ and they are $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}$$

$$ [\begin{aligned} y &= \frac{1}{3} r^3 \ \therefore \frac{dy}{dr} &= \frac{1}{3} 3 r^{3-1} \ \frac{dy}{dx} &= r^2 \ \therefore dy &= r^2 \cdot dr = r \cdot dr \cdot r \end{aligned}] $$

$$ \begin{equation} e^{\pi i} + 1 = 0 \end{equation} $$

The beautiful equation $\ref{eu_eqn}$ is known as the Euler equation.

$$ \begin{align*} x&=y & w &=z & a&=b+c\ 2x&=-y & 3w&=\frac{1}{2}z & a&=b\ -4 + 5x&=2+y & w+2&=-1+w & ab&=cb \end{align*} $$

$$ \begin{CD} A @>a>> B \ @VbVV @AAcA \ C @= D \end{CD} $$

something $\overbrace{a+b+c}^{\text{note}}$ or other

abc $$ \mathbf{P} = \begin{pmatrix} 3 & 1 \ 2 & 4 \end{pmatrix} $$ def

abc $\mathbf{P} = \begin{pmatrix} 3 & 1 \ 2 & 4 \end{pmatrix}$ def

$$ \begin{equation} e^{i \pi} + 1 = 0 \end{equation} $$

$$ \begin{equation} \label{linear} \mathbf{A}^{-1}\vec{b} = \vec{x} \end{equation} $$